Help me count the frequency respon of Marshall MG-30 power amp

Started by Agung Kurniawan, May 10, 2017, 05:06:43 PM

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Agung Kurniawan


Hi guys...
back a few day I was asking about FDD switch on marshall mg30 power amp and I get the function is to change the frequency respon of the power amp.
And now I have a lot of question since I get interested at marshall mg series power amp. I have a question about filter on this:
section.
there is some filter belong there, so the question is:
- what is the formula to count the filter frequency?
- can someone please do the math for me to take some example how to count them?
- is that any formula to count the power amp section gain of this amp?
- can I replace R37 and C39 with gyrators?
thanks :)
Multiple gain stage followed by some active EQ is delicious.

antonis

Quote from: Agung Kurniawan on May 10, 2017, 05:06:43 PM
- what is the formula to count the filter frequency?
The all time classic f3db cut-off = 1/(6.28xRxC)
(it also stands for every "sneaky" combination, like simple or twin T-notch filter..)

Quote from: Agung Kurniawan on May 10, 2017, 05:06:43 PM
- can someone please do the math for me to take some example how to count them?
You must be kidding...  :icon_cool:

Quote from: Agung Kurniawan on May 10, 2017, 05:06:43 PM
- is that any formula to count the power amp section gain of this amp?
Exactly the same formula which stands for EVERY inverting op-amp gain calculation ( Vout/Vin = - RF/RG)
(replace every cap with it's impedance (XC = 1/(6.28xfxC) at the frequency of interest (f) and calculate the series/parallel equivalent resistance(s)..)

Quote from: Agung Kurniawan on May 10, 2017, 05:06:43 PM
- can I replace R37 and C39 with gyrators?
No, because you'll also come back and ask for filter formulas & math calculation chores..

Quote from: Agung Kurniawan on May 10, 2017, 05:06:43 PM
thanks :)
You're wellcome..  :)
"I'm getting older while being taught all the time" Solon the Athenian..
"I don't mind  being taught all the time but I do mind a lot getting old" Antonis the Thessalonian..

teemuk

Do also note that practical load is reactive and will have an impedance. Current feedback will increase effective output impedance and voltage gain becomes load-variant. Which is the whole point of frequency dependant damping.