Howdy!
I built a Fender Jazz Bass Preamp, but it calls for a 20K Log taper pot for the level control. I have only a 50KA , will this be okay? I also have some 10KA, could they be made into a 20KA Pot?
I also have a 20KLinear Taper 3 Turns. Help........
If anyone can hep, please do....
Thanks!
Arn C.
http://www.tpub.com/neets/book1/chapter3/1-26.htm
1/Req = 1/R1 + 1/R2
1/20k = 1/50k + 1/R2
R2 = ~ 33K
I think you can just solder R2 across the outer lugs (1 and 3). Maybe a guru can confirm this, or explain why it wouldn't work :)
Thanks John!
Does anyone else have any other suggestions ?
Thanks!
Arn C.
50k will work fine, it may sound a bit brighter and your output impedance may be increase a bit, but really there will be hardly any difference.
Soldering the resistor across the lugs will work, but the taper of the pot will be messed up. That formula only takes into account when the pot is at max (i.e 0k on one side, 50k on the other side).
John,
I did what you said and it worked great!!!
Thanks a Bunch!!!!
Arn C.