Illuminated 3PDT switch lighting up in bypass

[Widows]

Hi, I'm building a guitar pedal with one of those illuminated 3PDT foot switches on a daughter board routed for true bypass but I think maybe the routing is flipped/reversed as the thing lights up when the pedal is in bypass, and turns off when engaged; the opposite of what I want.

If I was to twist the legs coming from the LED array on the foot switch so the polarity is reversed (positive leg to negative pad on board etc), would that fix things, or would I just wind up with a switch that doesn't light up at all??

Just looking for some advice before I start hacking away at it. Cheers

[idy]

 No, reversing the polarity of the LED will not help.
What daughter board are you using (photo?) Often they don't come with schematics so tough to tell..

What is happening is at the LED is getting power on the wrong "throw" of the "Double Throw Triple Pole."
Usually the footswitch provides a path to ground to for the LED when pedal is engaged. Sometimes that ground si used in bypass to ground (silence) the input of the circuit.

You will find that (test with power off) one middle lug of the switch is grounded all the time, and that pressing the switch changes whether the lug above or below is grounded. One of those two (the wrong one now!) is connected to the LED and you need to change that out.

[Kevin Mitchell]

Things can be pretty backwards when you work upside-down 

Reversing the LED polarity will destroy them.
Swap the top & bottom lug's pedal wiring around leaving the center connections the same.

[Widows]

I feared as much. The board is my own design so I must've got something backwards in the beginning.
I'll see if I can dig out the designs tomorrow, some of the tracks are routed under the switch so it's hard to tell what goes where once the switch is installed and it's been a while since I designed it so the layout is not so fresh in my mind.

Thanks for your help both of you

[Widows]

Yep so it looks like I had the +ve rail connected to both the LED +ve pad and the switch lug between the lugs connected to the board's in and out pads, *and* the -ve pad for the LED was routed to GND.

I've redesigned it so the -ve pad of the LED is no longer connected directly to GND, but runs to the switch lug between the board in and out lugs. The power rail from the CLR runs to the LED's +ve pad only and is no longer connected to the lug between the board in/out lugs.

[Kevin Mitchell]

Yep so it looks like I had the +ve rail connected to both the LED +ve pad and the switch lug between the lugs connected to the board's in and out pads, *and* the -ve pad for the LED was routed to GND.

I've redesigned it so the -ve pad of the LED is no longer connected directly to GND, but runs to the switch lug between the board in and out lugs. The power rail from the CLR runs to the LED's +ve pad only and is no longer connected to the lug between the board in/out lugs.

Sorting this in my head was a mental rollercoaster 
You could always share your layout if you have doubts.
Good luck!

[ElectricDruid]

Remember that it doesn't matter whether the LED hangs off the +V down to the switch, or off the switch down to ground. If you've got the switch connected to +V, then perhaps all you need to do is connect the LED from the switch so the cathode goes to ground (with series resistor, of course!).

It boils down to whether you put the switch in the +V side or the Ground side of the LED's connections to power. Doesn't matter which, technically speaking. Sometimes one is more convenient than the other for whatever reason.

HTH