Does the making a linear pot into an audio taper pot also then apply when wiring it as two parallel variable resistors? Im trying to get my head around whats happening both resistors (parallel) being controlled by the same shaft.

No, parallel variable resistors will give you a linear variable resistor with half the value of each pot.

The way to think about it is this. Parallel resistors give a total resistance of Rtot = R1*R2/(R1+R2).

E: If the two gangs are both wired to increase resistance clockwise (in goes to lug 1, out from lug 2, or vice-versa), then R1 = R2 = X*r, where X is the value of the pot, and r is the rotation percentage. So Rtot = R1

^{2}/(2*R1) = R1/2 = X*r/2

F: If the two gangs are both wired to increase resistance counterclockwise, then R1 = R2 = X(1-r), so Rtot = X(1-r)/2.

G: If you want to try something crazy and wire one to increase clockwise and the other to increase counterclockwise, you get Rtot = X(r-r

^{2}), which is a parabola. (The steps are left as an exercise for the reader.)

If you want to see the math behind the voltage divider plots above, let me know and I'll post it.