Hey all...
I have a question that I hope someone can help me with:
I have an Orange amplifier head that provides ~ 7.6VDC on the jack that you plug the channel switch into.
The amp doesn't come with a switch, so I wanted to build my own.
Closing the switch is obviously easy to do (and works fine), but I am adding an LED for BOTH states of the switch (closed and open) and want to use the provided 7.6VDC to power the LEDs.
Right now I come off of the tip of the input jack (which carries the + from the amp) and hit a DPDT switch.
The circuit looks like this:

The 7.6VDC comes from the amp and hits a DPDT with the two center pins tied together (to provide voltage to the amp side and the LED side).
When the DPDT is open for the amp, LED 1 lights without any problem.
When the DPDT is closed for the amp, the amp switches (as it should), but LED 2 doesn't light.
I am assuming that the LED is providing enough resistance so that the electricity just grounds out on the amp side, but I'm not sure how to correct it.
Any ideas?
I'd like to avoid putting a 9-volt source in there if possible.
Also, I am currently using two LEDs I just grabbed from RadioShack... one is a 1.7v 20 mA and the other is a 5v 30mA. Both are PLENTY bright with the 1k resistor, but am I hurting anything with those voltage of LEDs?
Thanks a bunch!
Jim Coates