Hi everyone, nice to meet y'all...
I know this general topic has been beat to death here and on just about every other DIY pedal forum, but even after combing many threads and diagrams I'm still not 100 percent sure I have the right idea so I decided to just ask here. Hopefully it's not too annoying of a question....

For the unfamiliar - the Brutalist JR is an easy PCB based kit based on the Providence Stampede pedal.
For my build, I'd like to add two SPDT on/off/on switches, one for either clipping diode position, such that a user could toggle between a total of 9 different combinations. My main issue is that I can't quite figure out exactly where I need to come in and out from the PCB. I understand that since LED's have a larger
Vf they should be connected such that they are selected when the switch is in the OFF position, correct?
My hypothesis Using an SPDT on/off/on switch, I'm assuming that I would need to have
a lead from the corresponding anode position on the PCB that would
connect to the anodes of two different diodes. Each of the
cathodes of the aforementioned components
would then connect to either outer lug of the switch separately, and the common lug of the switch would then have an LED (I'm assuming anode goes to the lug?) connected to it, with a lead connecting that to the corresponding cathode position on the PCB.
Are my instincts correct, or am I way off base here? If it turns out to be the latter, I would greatly appreciate a visual aid and an explanation of the flaws in my logic. I'm really trying to gain a solid understanding of the "why" when it comes to circuits. (I swear I don't normally need to be spoonfed this hard

- I've been lurking for quite some time now). Thanx and infernal hails in advance for any help

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Schematic
Not my build but included for more reference